Conservation of linear momentum
According to principle of conservation
of linear momentum in case of perfectly elastic collision both the linear
momentum and kenetic energy of system conserved
imp---
if mass of balls are same than after
the collision it exchanges the velocity
Now let us suppose that the ball is
moving toward a wall
P(initial)= (m*v)*i , (i
denote the motion in only x direction)
P(final)= -(m*v)*i ,
So change in momentum of ball
=p(f) – p(i) ,
=(-2mv)*i
Now let suppose there are ‘n’ no of molecules in the container having
possible velocity
V1=(Vx1)i +(Vy1)j +(Vz1)k
V2=(Vx2)i +(Vy2)j +(Vz2)k
.
.
.
.
Vn=(Vxn)i +(Vyn)j +(Vzn)k
Pressure on the wall due to x-component
of velocity
For ball
change in momentum of ball
=p(f) – p(i) ,
=(-2mv)*i
For wall
change in momentum of ball
=p(f) – p(i) ,
=(2mv)*i
2l/v sec = time taken in 1 collision
I sec =v/2l collision
F= p*frequency
=2mv*v/2l
=mV2/l
F(x)= mv2/l(x1) + mv2/l(x2) +
mv2/l(x3)…………..mv2/l(xn)
As
Pressure =force/area
=and area=L*L
Pressure in x direction= mV2/L +mv2/L +
mv2/L+……………mv2/L
1 + 2
+ 3 +…………….
N
Same as pressure in Y direction
= mV2/L +mv2/L + mv2/L+……………mv2/L
1 + 2
+ 3 +…………….
N
And
Z-direction
= mV2/L +mv2/L + mv2/L+……………mv2/L
1 + 2
+ 3 +…………….
N
Now according to pascal law the
pressure on any surface of container is always
same means by all component
So
Px = Py = Pz = P
Adding all the pressure
P + P +P =m(V2 + V2 + V2……….. V2)/L3
1 2 3 n
3P = m(V2 + V2 + V2……….. V2)/L3
1 2
3 n
P= m(V2 + V2 + V2……….. V2)/3*L3
1 2
3 ............. n
L3=V(volume of container)
P = = m(V2 + V2 + V2……….. V2)/3*V
1 2
3 n
This is nothing but maxwell’s theory of
kenetic gases
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